Formula 1 Li(τ)=1Di[ln(X(i+1)−τ)−ln(X(i)−τ)]\mathrm{L}_{\mathrm{i}}(\tau)=\frac{1}{\mathrm{D}_{\mathrm{i}}}\left[\ln \left(\mathrm{X}_{(\mathrm{i}+1)}-\tau\right)-\ln \left(\mathrm{X}_{(\mathrm{i})}-\tau\right)\right]Li(τ)=Di1[ln(X(i+1)−τ)−ln(X(i)−τ)]