G-1Rectangular sections
IS 456:2000, Plain and Reinforced Concrete — Code of Practice
Last Updated 29 Oct 2026
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G-1.1 Sections Without Compression Reinforcement
The moment of resistance of rectangular sections without compression reinforcement should be obtained as follows:
- a) Determine the depth of netutral axis from the following equation:
dxu=0.36fckb.d0.87fyAst
b) If the value of xv/d is less than the limiting
- If the value of αyd is less than the limiting value (see Note below 38.1), calculate the moment of resistance by the following expression:
Mu=0.87fyAstd(1−bdfckAstfy)
- c) If the value of xu/d is equal to the limiting value, the moment of resistance of the section is given by the following expression :
Mu⋅lim=0.36dxu,max(1−0.42dxu,max)bd2fck
- d) If xu/d is greater than the limiting value, the section should be redesigned.
In the above equations,
= depth of neutral axis,
d= effective depth,
fy= characteristic strength of reinforce- ment,
As= area of tension reinforcement,
= characteristic compressive strength of concrete,
b= width of the compression face,
Mu,lim= limiting moment of resistance of a section without compression reinforcement, and
xu, lima = limiting value of xu from 39.1.
G-1.2 Section with Compression Reinforcement
Where the ultimate moment of resistance of section
exceeds the limiting value, Mu, lim compression reinforcement may be obtained from the following equation :
Mu−Mu,llm=fnoAno(d−d′)
where
Mu,Mu, lim, d are same as in G-1.1,
fc= design stress in compression reinforce-
ment corresponding to a strain of
0.00035 (xu,maxxu,max−1)
where
xu,max= the limiting value of xu from 38.1.
= area of compression reinforcement, and
d′ = depth of compression reinforcement from compression face.
The total area of tension reinforcement shall be obtained from the following equation :
Ael=Ael1+Ael2
where
As= area of the total tensile reinforcement,
Ast1= area of the tensile reinforcement for a singly reinforced section for Mu,lim′ and
AM2=Ascfsc/0.87fy